Exam Code: 200-125
Certification Provider: Cisco
Certification Exam Name:CCNA Routing & Switching
Update Date: Apr 22,2024
Jul 20 2012 23:59 // Old prefix 0xFFFF Metric =0 0200 – 03FF Image The IP configuration is as above. The R2 interface is configured with two IP addresses, and both have announced that the entire network runs RIP . Assume that R1 is the stub node in the network structure. Therefore, on R2 , the extra routes are filtered out, and only the F1 and 0- port routes of R3 are advertised to R1 . We filter out specific routes on R2 : Used by IPv6 nodes to send messages to themselves. PE1#show bgp vpnv6 unicast all 2001:5555::5/128 If R2 on ip route 1.1.1.0 255.255.255.0 null0 ,ccna 200-125 dumps 2018, this time there is no routing table OSPF of 1.1.1.0 routing the unsuccessful thus re-release, so R3 can not learn the 1.1.1.0/24 route; 2000 – 3FFF The uniqueness of the MAC address guarantees the uniqueness of the interface ID . So in fact, it is very simple, as long as the prefix and mask part of the route, respectively, use the source and destination parts of the ACL to match. Image Use " ipv6 neighbor ipv6 address interface number mac address" to add a static entry to the neighbor discovery table, for example: No bgp default ipv4-unicast neighbor 2.2.2.2 remote-as 234 Ipv6 address 2001:23::2/64 0000 – 00FF Router ospf 100 [Two times of prefix] The configuration of PE1 is as follows: ! AFI (Address family identifier) We mainly analyze: Protocol ID: 0x86DD Tunnel source Serial0/0 tunnel mode ipv6ip 6to4 1/128 Associate route-map when route is re-published 6to4 relay Router ospf 100 MAC address mapping for IPv6 multicast addresses LSPID Image The extended header is optional. Only the function corresponding to the extended header is required, and the sending host adds the corresponding extended header. 9 1/32 twenty two Let's start with the above picture, starting from 172.16.0.0/16 . The next network number we see is 172.16.10.0/24 , which is obviously obtained after applying the VLSM variable length subnet mask. a 172.16.0.0/16 a master class this network subnet . So the so-called subnet, we can understand as a network number obtained by "stretching" the mask or borrowing from the host bit based on the default mask length of the category to which the network number belongs. In fact, 172.16.0.0/16 is an interval that includes 172.16.10.0/24 .
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